Print Version

[Neels]

Greetings,

Please have some patience as I'm not a python/web/html/soup developer

I am trying to return the print version of an article from an rss feed. The url looks something like this:

http://www.news24.com/Content/SouthA...intenance_bill

The print version url looks like this:

http://www.news24.com/printArticle.a...aff46&cid=1059

The problem is that the print url is supplied through a java script:
<script language="JavaScript">
function openPrintWindow() {
myPrintWindow = window.open('http://www.news24.com/printArticle.aspx?iframe&aid=1cfd873e-535e-4b5a-b944-da15f15aff46&cid=1059','myPrintWindow','toolbar=0, location=0,directories=0,status=0,menubar=0,scroll bars=1,resizable=0,width=750,height=600');
}
</script>

So, what is the easiest way to grab that URL from the java script? I've looked at some of the builtin recipes but could not find anything that relates to a specific case like this. Or maybe I just didn't understand the python code

Any help appreciated.
Regards,
Neels

[kovidgoyal]

use a regular expression to match the text in the javascript.

[Neels]

Ok,

A little example:
Q: How do I travel from Z to Y?
A: Use an automobile.

Not to belittle the regular expression answer, but .... uhhmmmm HOW? Does anyone have some sample code using regular expressions?

Regards,
Neels

[kovidgoyal]

is the javascript in the feed file or in the html linked to by the rss feed?

[kiklop74]

This is what you should use:

    def print_version(self, url):
        artl = url.rpartition('/')[0]
        artl2 = artl.rpartition('/')[0]
        rrest, sep, aid= artl3.rpartition('/')
        cid = rrest.rpartition('/')[2]
        return 'http://www.news24.com/printArticle.aspx?iframe&aid=' + aid + '&cid=' + cid

[Neels]

Thanks!! Will try that tonight. Much appreciated.

<edit>

PERFECT. I will study it a bit as there is another site using a similar method and post both recipes when done.

Thanks again.