Template : IF code is correct?

[un_pogaz]

So I looked at the code of the Template function (for build a 'IFELSE') and I just saw the 'IF' code is that:

def evaluate(self, formatter, kwargs, mi, locals, x, y, re):
    if val:
        return val

It's very strange, it shouldn't rather be :

def evaluate(self, formatter, kwargs, mi, locals, x, y, re):
    if x == y:
        return re

calibre 5.7.2

(I sincerely hope I'm wrong, otherwise there's a very old bug.)

[chaley]

What exactly are you looking at?

The line

def evaluate(self, formatter, kwargs, mi, locals, x, y, re)

doesn't exist in calibre.

The lines

if val:
        return val

exist in the ifempty function, and are correct.

[un_pogaz]

My bad. My bad.
This function "IF(x, y, re)" is a custom function. I have no idea how it got into my Caliber parameters, as this is the first time I create Template functions.

[chaley]

Originally Posted by un_pogaz

My bad. My bad.
This function "IF(x, y, re)" is a custom function. I have no idea how it got into my Caliber parameters, as this is the first time I create Template functions.

Thanks for telling me.

BTW: the template language supports if/then/else. It is evaluated directly by the template processor (inlined) and has much better performance than a function.

[un_pogaz]

Originally Posted by chaley

BTW: the template language supports if/then/else. It is evaluated directly by the template processor (inlined) and has much better performance than a function.

Oh, perfect, Thanks