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Old 05-15-2011, 10:53 AM   #1
xXxXxXxXxXx
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Recipe for cosmopolitan US

J'd like to create recipe for cosmopolitan US

J want to use print version and in order to do that J need to change url of articles.

for instance:

from:

http://www.cosmopolitan.com/sex-love/dating-advice/tips-for-long-distance-relationships?src=rss

to:

http://www.cosmopolitan.com/print-this/tips-for-long-distance-relationships?src=rss

and J don't know how to do this?

any help?

this is source code:
Code:
class AdvancedUserRecipe1305470859(BasicNewsRecipe):
    title          = u'Cosmopolitan'
    oldest_article = 14
    max_articles_per_feed = 100

    feeds          = [(u'Sex & Love', u'http://www.cosmopolitan.com/sex-love/rss/'), (u'Hair & Beauty', u'http://www.cosmopolitan.com/hairstyles-beauty/rss/'), (u'Celebs & Style', u'http://www.cosmopolitan.com/celebrity/rss/'), (u'Secrets & Advice', u'http://www.cosmopolitan.com/advice/rss/')]

Last edited by xXxXxXxXxXx; 05-15-2011 at 11:24 AM.
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Old 05-16-2011, 08:37 AM   #2
schuster
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try this

Code:
class AdvancedUserRecipe1305470859(BasicNewsRecipe):
    title          = u'Cosmopolitan Magazin'
    oldest_article = 14
    max_articles_per_feed = 20
    no_stylesheets         = True
    use_embedded_content   = False
    remove_javascript      = True
    cover_url = 'http://www.cosmopolitan.com/cm/shared/site_images/print_this/cosmopolitan_logo.gif'
    extra_css = '''
                    h2{font-family:Arial,Helvetica,sans-serif; font-size: x-small;}
                    h1{ font-family:Arial,Helvetica,sans-serif;  font-size:x-large; font-weight:bold;}
                '''
    remove_tags = [dict(name='div', attrs={'class':'printTools'})]

    def print_version(self,url):
          segments = url.split('/') 
          printURL = '/'.join(segments[0:3]) + '/print-this/' + '/'.join(segments[4:])
          return printURL

    def preprocess_html(self, soup):
        for alink in soup.findAll('a'):
            if alink.string is not None:
               tstr = alink.string
               alink.replaceWith(tstr)
        return soup

    feeds          = [(u'Sex&Love', u'http://www.cosmopolitan.com/sex-love/rss/'),
                          (u'Hair&Beauty', u'http://www.cosmopolitan.com/hairstyles-beauty/rss/'),
                          (u'Celebs & Style', u'http://www.cosmopolitan.com/celebrity/rss/'),
                          (u'Secrets & Advice', u'http://www.cosmopolitan.com/advice/rss/'),
                          (u'Sexy Beauty Secrets Blog', u'http://www.cosmopolitan.com/hairstyles-beauty/beauty-blog/rss/'),
                          (u'Joe Hottie`s Dating Blog', u'http://www.cosmopolitan.com/sex-love/joe-hottie/joe-hottie-rss/'),
                          (u'Bedroom Blog', u'http://www.cosmopolitan.com/sex-love/bedroom-blog/rss/')]
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Old 05-16-2011, 08:56 AM   #3
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Thank you,
J want to create my own recipe, but J always have problems with changing url to print version,

Could you explain this: (write comment in each line what you do )?

def print_version(self,url):
segments = url.split('/')
printURL = '/'.join(segments[0:3]) + '/print-this/' + '/'.join(segments[4:])
return printURL

def preprocess_html(self, soup):
for alink in soup.findAll('a'):
if alink.string is not None:
tstr = alink.string
alink.replaceWith(tstr)
return soup
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Old 05-16-2011, 09:08 AM   #4
schuster
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Quote:
Could you explain this:
the explanation is better given from the original sources, i think


Code:
https://www.mobileread.com/forums/showpost.php?p=1231995&postcount=9
Code:
https://www.mobileread.com/forums/showpost.php?p=1488098&postcount=4
hope this helps

greetings
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Old 05-16-2011, 09:51 AM   #5
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Quote:
Originally Posted by schuster View Post
the explanation is better given from the original sources, i think
I've added the description of split/join for URL modification in the print_version context into the code sticky. This question is often asked. See the links there.

https://www.mobileread.com/forums/sho...9&postcount=12
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Old 05-16-2011, 10:23 AM   #6
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good idea
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