Lost trying to get url for time.com cover

[Olger]

Hi All,
I've got a time.com recipe based on the publically available RSS from the site, and am trying to make it all nice and pretty and get the current cover for it.
On the page http://www.time.com/time/coversearch
the first cover is the most recent one.
I figured that I would have to search the page for : <ul class="ul-covers"> and then grab the first url within the <figure class="entry-content"> tag.
Problem is, how to code it?
I've had a look at Kovids time mag example, but that requires logging into the website and as I stated, my python just isn't that good (yet).
Anyone have an idea?

Cheers! Olger.

[kovidgoyal]

The builtin Time recipe does not require a login and gets the cover.

[Olger]

Hi Kovid,
Yeah, I did notice that (sorry for the delayed reply, been a bit busy). But trying to modify that recipe with RSS feeds turns out not so easy.
Are there other recipes that grab the cover by parsing a html page looking for matches that are easier to modify?
Cheers! Olger

[marlenunez]

The website kiosko.net has covers for most of the important periodicals out there, including Time.

This code, adapted from a post by user miwie, will give you the current cover for Time if you run the recipe either on Sunday or Monday:

from time import strftime
...
	def get_cover_url(self):
		return 'http://img.kiosko.net/' + strftime("%Y/%m/%d") + '/us/time.750.jpg'

http://en.kiosko.net/us/np/time.html

http://img.kiosko.net/2012/02/13/us/time.750.jpg