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#5116 | ||
Opsimath
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[QUOTE=Stitchawl;1908684]
Quote:
Quote:
Some famous somebody said that they believed that the island of Guam was going to flip over because of all the building that was going on in the western side of the island. The poor guy didn't realize that Guam is the exposed tip of a huge undersea mountain, not some pancake floating in the ocean! |
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#5117 |
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I don't know about a baby mountain range, but the island of Krakatoa has been reforming since the 1883 eruption.
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#5118 | |
Opsimath
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Stitchawl |
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#5119 |
The Grand Mouse 高貴的老鼠
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#5120 | |
Opsimath
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Give us a question, if you please, Paul! Stitchawl |
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#5121 |
The Grand Mouse 高貴的老鼠
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Hmmm... OK. Here's a probability question.
I deal out four cards face down from a shuffled standard deck of 52 cards. My friend looks at them (without showing me), and tells me that if I turn over any two of them, I have a 50% chance of getting two red cards. What are my chances of turning over two of the cards and getting two black cards? (You may assume that my friend is both truthful and good at probability calculations.) |
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#5122 |
Grand Sorcerer
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0%.
There's three red cards and one black card. So how can one verify this? In order to figure out the probability of drawing two red cards from those four cards (3 red and 1 black) it is: Probability of drawing a red card on the first pick = 3/4 or 75% Probability of drawing a red card on the second pick = 2/3 or 67% 75% * 67% = 50% It seems odd, but it is often easier to think about the combinations involved. We have R1, R2, R3, and B1 as the four cards (first red, second red, third red, and first black). You could draw two cards from this set in 12 different ways: R1 R2 R1 R3 R1 B1 R2 R1 R2 R3 R2 B1 R3 R1 R3 R2 R3 B1 B1 R1 B1 R2 B1 R3 Take out all the ones without two reds and you're left with; R1 R2 R1 R3 R2 R1 R2 R3 R3 R1 R3 R2 Or six different combinations from the twelve. A 50% chance. |
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#5123 |
whimsical
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0%.
Well my way is no maths. Just... thinking and guessing, like this: 4C2 = 6 ways to draw 2 cards out of 4. And given that the chance to draw 2 red cards is 50%, so there are 3 ways to draw 2 red cards out of 4. Which means there must be 3 reds and 1 black, because if the number of reds is less than 3 it'll be impossible to draw 2 red cards in 3 different ways. |
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#5124 |
Grand Sorcerer
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How is 4C2 no maths?
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#5125 |
whimsical
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#5126 |
The Grand Mouse 高貴的老鼠
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#5127 |
Grand Sorcerer
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@maianhvk: lol. I don't think being able to google something makes it not of it's subject matter.
![]() Give me two examples of a pangram. |
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#5128 |
The Grand Mouse 高貴的老鼠
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Pack my box with five dozen liquor jugs.
Sphinx of Black Quartz, judge my vow. (Those are the two I always remember, apart from, of course, The quick brown fox jumps over the lazy dog.) |
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#5129 |
Grand Sorcerer
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#5130 |
The Grand Mouse 高貴的老鼠
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OK, another mathematical one.
The sum of an infinite series of terms can converge (the more terms you calculate, the closer the total gets to a particular value), diverge to infinity (the more terms you calculate the larger the number gets) or do neither. An example of a converging sequence is 1 + (1/2) + (1/4) + (1/8) + (1/16) + .... which converges to 2. An example of a diverging sequence is 1 + 2 + 3 + 4 +.... which obviously diverges to infinity. An example of a sequence that does neither is 1 + (-1) + 1 + (-1) + 1 + (-1) + .... Does the sequence 1 + (1/2) + (1/3) + (1/4) + (1/5) + .... converge or diverge? (It plainly does one or the other.) Can you provide a proof of your answer? |
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