Python help please

[AndyW1691]

I am trying to modify a template function without knowing Python. I'm sure it must be easy to do, but can't get the syntax correct. Here are the details:

The function has the statement 'date = mg.group(1)' which returns a string of the format 'mm/dd/yyyy'

What I want to do is to swap the order of the 'mm' & 'dd' so the final string has the form 'dd/mm/yyyy'. How do you do this in Python?

Thank you for your help.

Andy

[chaley]

There are lots of ways to do this ranging from changing the regexp to return more groups to reconstructing the string.

One way:

	if mg is None:
		return no_page_read_str
	date = mg.group(1)
	date = "{1}/{0}/{2}".format(*date.split('/'))
	pct = mg.group(2)

EDIT: The *date stuff unpacks the list (array) into positional parameters as required by the "format" method. It is explained in the python docs here.

Another way, less magic:

	if mg is None:
		return no_page_read_str
	date = mg.group(1)
	parts = date,split('/')
	date = parts[1] + '/' + parts[0] + '/' + parts[2]
	pct = mg.group(2)

[AndyW1691]

Hi Chaley!

I used the second example you gave as it was more intuitive to me. There is a small error in that to get it to work I changed:

parts = date,split('/') to parts = date.split('/')

It now works exactly as I want it to.

Thank you very much...

[AndyW1691]

After evaluating different formats I eventually settled on using:

date = 'Read ' + parts[0] + '/' + parts[2]

For read books this now produces a column entry of the form "Read mm/yy"

I do so like calibre!