Django doc recipe ( need some tip )

[mauropiccolo]

Hi,
I wrote this recipe for read django documentation on my kindle.
( I like kindle news menu )
There is a better solution ? ( es not news recupe but something else?)

I like to manage "internal" link , so I need convert url like
<a class="reference internal" href="../../ref/contrib/admin/#django.contrib.admin.ModelAdmin.fieldsets" ......</a>

to something like
<a class="reference internal" href="/feed_1/article_15/index.xhtml#django.contrib.admin.ModelAdmin.fields ets" ......</a>

1) there is already some function to do this ?
2) if not, where is the right place ( method name ) where:
- record download_url -> feed/article
- parse and substitute url
3) which is the correct format of new url ?

in the meantime I can try to fix errors like:
Referenced file u'/tmp/calibre_1.47.0_tmp_u8U8s8/pylBRj_plumber/feed_3/article_4/index.xhtml' not found
that seems correlated.

Hope You can understand regardless my bad english.

Regards, Mauro

[kovidgoyal]

The recipe system automatically rewrites any link that it follows and downloads. You need to use recursions and is_link_wanted() in your recipe to control which links are followed.

[mauropiccolo]

Thanks for response, but may be I need furter help.

here new recipe, with recursions and is_link_wanted() , but still link are not converted.

See the log, may be there is a bug in rewriting.

"Referenced file u'/tmp/calibre_1.47.0_tmp_HTY8tN/ZCDmzW_plumber/feed_4/article_79/index.xhtml' not found "

Calibre version 1.47 on ubuntu 14.04

Regards, Mauro

If it can help, pages are not downloaded because the link to follow,
but each page is like an article,
so must link to the right article.