MobileRead Forums - View Single Post - Error "Could not fetch link..." while creating a basic recipe

atlantique · 05-03-2012, 07:18 PM

The typical format of an url included in one of the rebelion.org rss feeds looks like this:

http://www.rebelion.org/noticias/ee....nicomio-148960

In order to avoid the 404 "Not found" problem, it is necessary to convert the URL
to the following format:

http://www.rebelion.org/noticia.php?...-al-manicomio-

Doing this for each of the url listed on the rss feed will solve your problem. However
I do not know how to do this using calibre/python regular expressions, although
one can presume that it must simple to do it, since it is rather straightforward
using set/awk.

Let us hope that one of the more knowledgeable users will help with this url
modification. Good luck!

05-03-2012, 07:18 PM	#2
atlantique Junior Member Posts: 4 Karma: 10 Join Date: May 2010 Device: kindle dx	The typical format of an url included in one of the rebelion.org rss feeds looks like this: http://www.rebelion.org/noticias/ee....nicomio-148960 In order to avoid the 404 "Not found" problem, it is necessary to convert the URL to the following format: http://www.rebelion.org/noticia.php?...-al-manicomio- Doing this for each of the url listed on the rss feed will solve your problem. However I do not know how to do this using calibre/python regular expressions, although one can presume that it must simple to do it, since it is rather straightforward using set/awk. Let us hope that one of the more knowledgeable users will help with this url modification. Good luck!