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ElMiko · 05-17-2025, 04:21 AM

I'm trying to find instances of the following string

Code:

said. “

(where the quotation mark is a curly opening quotation mark)

I want to exclude matches where the string is preceded by a word, preceded by a closing curly quotation mark. e.g.

Code:

” Jack said. “

My solution for this would be a regex search like:

Code:

(?<!”\s\w+?\s)said\. “

However, as soon as I add the quatifier "+" I get the error message for invalid Regex.

I was under the impression that 2.4.2's regex natively allows for indefinite length lookbehinds. What am I doing wrong? Is there some a different syntax that needs to be used for indefinite length lookbehinds?

05-17-2025, 04:21 AM	#1
ElMiko Addict Posts: 397 Karma: 65460 Join Date: Jun 2011 Device: Kindle	Indefinite length lookbehind I'm trying to find instances of the following string Code: said. “ (where the quotation mark is a curly opening quotation mark) I want to exclude matches where the string is preceded by a word, preceded by a closing curly quotation mark. e.g. Code: ” Jack said. “ My solution for this would be a regex search like: Code: (?<!”\s\w+?\s)said\. “ However, as soon as I add the quatifier "+" I get the error message for invalid Regex. I was under the impression that 2.4.2's regex natively allows for indefinite length lookbehinds. What am I doing wrong? Is there some a different syntax that needs to be used for indefinite length lookbehinds? Last edited by ElMiko; 05-17-2025 at 05:15 AM.