[ackomb]

Originally Posted by chaley

Assuming your indenting is correct then the missing 'fi' is needed to close the if/elif that begins on line 6.

Getting there it was actualy still missing a "else ni" statement for it to work.

program:
output = '';

	for item in $#pair:
		if $#show == "show A, Show B" then
			if item ==  "ABC/XYZ" then ni = "AAA / BBB"
			elif item ==  "DEF/UVW" then ni = "CCC / DDD"
			else ni = item
			fi
		else ni = item
		fi;
		output = output & ',' & ni
	rof;
	output = list_sort(list_remove_duplicates(output, ','), 0, ',')

But it only works now if it only contains show A and show B in that specific order. But as soon as there is a Show C, which is not interfering with the pairing it does not work anymore.

That means the first if statment should be something like:

if $#show contains item "show A" and "Show B" then

Of course this does not work but how would, so I tried:

if $#show != "Show A" && "Show B" then

This seems to work. Just thought I would post it for others researching something similar.