[chaley]

Originally Posted by Wiggo

program:
	icon1 = if $$languages == 'englisch' then 'uk.png' else '' fi;
	icon2 = if $$#read == 'true' then 'ok.png' else  '' fi;
	icon3 = if $$#redl == 'true' then 'auto-reload.png' else '' fi;
	icon4 = if $$#toread == 'true' then 'reference.png' else '' fi;
	icon1 & ':' & icon2 & ':' & icon3 & ':' & icon4

I don't get language to work and not a 3x condition for #read (true, false, not defined).

I think you want something like this.

program:
	def add_icon(icon, val):
		if icon == '' then icon = val else icon = icon & ':' & val fi;
		return icon
	fed;

	icon = '';
	if $languages == 'eng' then icon = add_icon(icon, 'uk.png') fi;
	icon = add_icon(
		icon, 
		switch(
			$$#read,
			'true', 'ok.png',
			'false', 'false_icon.png',
			'unset_icon.png'));
	if $$#redl == 'true' then add_icon(icon, 'auto-reload.png') fi;
	if $$#toread == 'true' then add_icon(icon, 'reference.png') fi;
	return icon

Rationale:

• The language code check must look for the three-letter value as shown in this web page, not the full language name. If you want to indicate other languages then use a switch() as explained below.
• Using $$ (raw_field()) of a tristate boolean returns one of three values: "true", "false", and "none". These are not translated.
• The switch function is a good substitute for a sequence of if/then/elif/else that check string matches.
• It is best for performance not to have empty values separated by colons. The add_icon function takes care of that by adding the colon only if the icon string already has a value.