[PoP]

Thought it would be fun and



to create a proportional font only from the 11 Box Drawing characters. So here is one!

With double line characters with kerning:

./box 0 0 4 "AaBbCcDdEeFfGgHhIiJjKkLlMmNnOoPpQqRrSsTtUuVvWwXxYyZz" -c

With double line characters and no kerning:

./box 0 0 4 "AaBbCcDdEeFfGgHhIiJjKkLlMmNnOoPpQqRrSsTtUuVvWwXxYyZz" -c -k

With single line characters with kerning:

./box 0 0 4 "AaBbCcDdEeFfGgHhIiJjKkLlMmNnOoPpQqRrSsTtUuVvWwXxYyZz" -c --k -d

With single line characters and no kerning:

./box 0 0 4 "AaBbCcDdEeFfGgHhIiJjKkLlMmNnOoPpQqRrSsTtUuVvWwXxYyZz" -c -k -d

Caveat¹: it is written in shell, so it is terribly inefficient, and also probably buggy (ouch UTF-8 handling).
Caveat²: Some characters need to be refined, maybe kerning rules too, you are welcome to improve.

[EDIT 2018-10-03] Get it from this version posted further in the thread