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roger64 · 06-16-2016, 10:10 AM

@jbacelar

Thanks very much.

This code is working very well for one punctuation sign. I tried to make it work for a second one but I probably did something wrong because it failed. I have been told indentation is tricky but between theory and practice...

So, I tried this... No

Code:

def replace (match, number, file_name, metadata, dictionaries, data, functions, * args, ** kwargs):
     return match.group().replace ("!","@!")

def replace (match, number, file_name, metadata, dictionaries, data, functions, * args, ** kwargs):
     return match.group().replace ("?","@?")

Should I create several functions like your own or is there a way to concatenate several of them in a single one (or even better group several punctuation signs replacement in the same command)?

06-16-2016, 10:10 AM	#190
roger64 Wizard Posts: 2,625 Karma: 3120635 Join Date: Jan 2009 Device: Kindle PW3 (wifi)	@jbacelar Thanks very much. This code is working very well for one punctuation sign. I tried to make it work for a second one but I probably did something wrong because it failed. I have been told indentation is tricky but between theory and practice... So, I tried this... No Code: def replace (match, number, file_name, metadata, dictionaries, data, functions, * args, ** kwargs): return match.group().replace ("!","@!") def replace (match, number, file_name, metadata, dictionaries, data, functions, * args, ** kwargs): return match.group().replace ("?","@?") Should I create several functions like your own or is there a way to concatenate several of them in a single one (or even better group several punctuation signs replacement in the same command)?