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AlPe · 04-17-2015, 12:59 PM

Yes, when merging more dictionaries into one, order of the (word, definition) is the same as the order of the input dictionaries. That is:

Code:

Input D1: (word1, defA), (word1, defB), (word2, defC)
Input D2: (word0, defD), (word1, defE), (word2, defF), (word2, defG)
Output D1+D2: (word0, defD), (word1, defA), (word1, defB), (word1, defE), (word2, defC), (word2, defF), (word2, defG)

=== === ===

Note that with the latest version (2.0.2), you can specify the

--merge-definitions

flag, which will collapse all the (word, def1), ..., (word, defN) into a single index entry (word, def1 ... defN), i.e. it concatenates the definitions from all the input dictionaries. Continuing the example above:

Code:

Output D1+D2 (with --merge-definitions):
(word0, defD)
(word1, defA defB defE)
(word2, defC defF defG)

There is also --merge-separator=STRING to specify the separator to be used when merging:

Code:

Output D1+D2 (with --merge-definitions and --merge-separator=" | "):
(word0, defD)
(word1, defA | defB | defE)
(word2, defC | defF | defG)

04-17-2015, 12:59 PM	#111
AlPe Digital Amanuensis Posts: 727 Karma: 1446357 Join Date: Dec 2011 Location: Turin, Italy Device: Several eReaders and tablets	Yes, when merging more dictionaries into one, order of the (word, definition) is the same as the order of the input dictionaries. That is: Code: Input D1: (word1, defA), (word1, defB), (word2, defC) Input D2: (word0, defD), (word1, defE), (word2, defF), (word2, defG) Output D1+D2: (word0, defD), (word1, defA), (word1, defB), (word1, defE), (word2, defC), (word2, defF), (word2, defG) === === === Note that with the latest version (2.0.2), you can specify the --merge-definitions flag, which will collapse all the (word, def1), ..., (word, defN) into a single index entry (word, def1 ... defN), i.e. it concatenates the definitions from all the input dictionaries. Continuing the example above: Code: Output D1+D2 (with --merge-definitions): (word0, defD) (word1, defA defB defE) (word2, defC defF defG) There is also --merge-separator=STRING to specify the separator to be used when merging: Code: Output D1+D2 (with --merge-definitions and --merge-separator=" \| "): (word0, defD) (word1, defA \| defB \| defE) (word2, defC \| defF \| defG)