[Alt68er]

Hi,
and first of all: many many thanks for your help and other comments.
In the meantime I found a solution which works absolutely fine for me:

find:    '\b\s{0,1}\.\.\.'
replace: ' …' or ' …'

The ' are used only to show exactly start and end of "code".

@ cybmole: You are right.
The most important rule is: the hellip is preceded by a blank when it replaces missing word(s), and not when it replaces missing letters of a word only.

In my case this doesn't matter because min. 99% of the 3 dots are replacing missing words.

Thanks again and have a nice day.
Peter