[twobob]

I'm reading here: http://en.wikibooks.org/wiki/C_Progr..._dereferencing

Pointers in Function Arguments

Often we need to invoke a function with an argument that is itself a pointer. In many instances, the variable is itself a parameter for the current function and may be a pointer to some type of structure. The ampersand character is not needed in this circumstance to obtain a pointer value, as the variable is itself a pointer. In the example below, the variable pStruct, a pointer, is a parameter to function FunctTwo, and is passed as an argument to FunctOne. The second parameter to FunctOne is an int. Since in function FunctTwo, mValue is a pointer to an int, the pointer must first be dereferenced using the * operator, hence the second argument in the call is *mValue. The third parameter to function FunctOne is a pointer to a long. Since pAA is itself a pointer to a long, no ampersand is needed when it is used as the third argument to the function.

 int FunctOne( struct SomeStruct *pValue, int iValue, long *lValue )
 {
    /*  do some stuff ... */
    return 0;
 }
 int FunctTwo( struct someStruct *pStruct, int *mValue )
 {
    int j;
    long  AnArray[25];
    long *pAA;
 
    pAA = &AnArray[13];
    j = FunctOne( pStruct, *mValue, pAA );
    return j;
 }

Um... What? Read's it several more times. sigh. get's tea