Originally Posted by Hamlet53

Assuming that the strategy is correct the odds of walking away with 160 is one minus the odds of losing a 18/37** bet 5* times in a row. That should be 1- {5!/[0!x5!] x (18/37)^0x(19/37)^5 }= 1- (19/37)^5 = 1-.036 = 0.964

I assume that 5 is the smallest allowed bet. Otherwise the smallest bet each time would improve the odds.

*160-5x{1+2+4+ ...+2^n) = 5 for n = 4

**odds of hitting red each spin for a wheel with 18 red, 18 black, and one green.