Quote:
Originally Posted by cybmole
easy with regex
find </p>\s*<p class ="calibre4">([a-z])
replace \1
NB the replace line has a space in front of \1
works with v4.2 regex, I have not upgraded to 0.5.1 yet.
pretty sure there are other threads on how to do this, a varienat for example is to test end of previous line for not fullstop not quote not questionmark |
This will catch about 98% of them. that do not end in punctuation.
My Wrap line Regex lightly tests the last character in the first line:
([\w",])</p>\s+<p class="calibre4">([\w"“…])
\1 \2
(there is a space between the \1 and \2)
This still misses:
...Dr.
Smith said...
...Mike
German ...