Thread: Silliness Quiz
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Old 01-04-2012, 05:34 PM   #5134
Bilbo1967
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Quote:
Originally Posted by pdurrant View Post
You're right that it diverges, but your proof isn't very elegant.

Here's the elegant proof.

Divide the series into groups as follows:

1 + (1/2 + 1/4) + (1/5 + 1/6 + 1/7 + 1/8) + (1/9 + 1/10 + 1/11 + 1/12 + 1/14 + 1/14 + 1/15 + 1/16) + ....

Replace each term in each group with the smallest term in the group. Note that this reduces the sum of the series.

1 + (1/4 + 1/4) + (1/8 + 1/8 + 1/8 + 1/8) + (1/16 + 1/16 + 1/16 + 1/16 + 1/16 + 1/16 + 1/16 + 1/16) + .....
Note that each and every group sums to 1/2

1 + (1/2) + (1/2) + (1/2) + .....

Which clearly diverges to infinity. Our original sequence has a larger sum than this, and so also diverges to infinity.

Q.E.D.

Hamlet53 gets to set the next question.
Sorry, why do you replace with the smallest term in each group? From my decidedly uninformed standpoint it just smacks of cheating.
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