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OK, I know interpreting this seriously is out of line, but really!!!???
The assumption is that a stored book is at a higher energy state than no book. However, what is stored is a bunch of 1's and 0's. It may well be that either a 1 or a 0 is a higher energy state depending on hardware definitions. Let's pretend that a 1 is higher energy.
An empty reader wouldn't be full of 0's. It would have a random mixture of 1's and 0's. The empty part would refer to the fact that there would be no directory entry showing that the space is used. However the space itself would not be all 0's. Then, when you load a book it doesn't change everything to 1's. It is some mixture of 1's and 0's to code the book.
You can't reliably predict that a stored book versus an empty memory is higher or lower in energy.
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