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chaley · 05-09-2011, 09:17 AM

Just for grins, what happens if you change that code to be:

Code:

for r in reversed(results):
    ans.identifiers.update(r.identifiers)

My thought is that if results is sorted highest-priority first, then processing them in reverse will leave the one you want. However, if identifiers is not ordered, then this suggestion is bogus.

EDIT: Never mind. 'results' is not a list.

05-09-2011, 09:17 AM	#2
chaley Grand Sorcerer Posts: 12,465 Karma: 8025600 Join Date: Jan 2010 Location: Notts, England Device: Kobo Libra 2	Just for grins, what happens if you change that code to be: Code: for r in reversed(results): ans.identifiers.update(r.identifiers) My thought is that if results is sorted highest-priority first, then processing them in reverse will leave the one you want. However, if identifiers is not ordered, then this suggestion is bogus. EDIT: Never mind. 'results' is not a list. Last edited by chaley; 05-09-2011 at 09:21 AM.