Quote:
Originally Posted by drMerry
Your last problem.
If books 1 and 2 are duplicates and 1 and 3 are duplicates. 2 and 3 will be (just like 3 and 1, 3 and 2 and 2 and 1) Isn't it?
That's why I think it is no problem.
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This was the subject of much discussion on the original thread referenced in the first post of this one, to do with the transitivity of groups.
Say in your library you have these two books:
#2 Foo (Omnibus)
#3 Foo
Now you run a duplicates check using similar title. It reports these books, as it will (in future) strip off stuff like (Omnibus). However you decide they are not duplicates of each other, so you mark the group as exempt.
Then at some point you add another book to your library (or maybe you changed the name for an existing book).
#1 Foo: Returns
When you run the duplicate check again, in the first pass it sees 1,2,3 as all being in the same duplicate group. However you have already said that 2 and 3 are not duplicates of each other. Nothing can be said from that about whether 1 matches 2 or 1 matches 3. So the user must be presented with two groups of the individual pairs.