Originally Posted by vivaldirules
Wait.  I took the square of the ratio of the distances. That's wrong. The diameter will be proportional to just the ratio of the distances. (duh! it's called "linear" perspective, doggie.) So the diameter will only be about 7% larger compared to when it is at its average distance. The apparent area will be proportional to the square of the ratio or 14% larger. The physical area will not be any larger but it will be closer so the moon should appear to be 14% brighter. Right? Or have I flunked high school math again?
Anyway, I'm pretty sure now that I won't notice the difference.
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