[BlonG]

Thank you very much! (I'm step closer to final version of recipe.)

I did come to next two "challenges". But let's take it step by step.

In recipe I use this code:

def print_version(self, url):
    split_url = url.split("/")
    print 'URL1= ', split_url[1]
    print 'URL2= ', split_url[2]
    print 'URL3= ', split_url[3]
    print 'URL4= ', split_url[4]
    print 'URL5= ', split_url[5]
    print 'URL6= ', split_url[6]
    print_url = 'http://www.rtvslo.si/index.php?c_mod=news&op=print&id=' + split_url[6]
    print 'THIS URL WILL PRINT: ',print_url
    return print_url

With this I found that ID of the article (six digit number) – needed for print version – is not always on same "place". Usually it’s under syntax split_url[6], but sometimes it’s at split_url[5].

So, the links to articles are like either this:

• http://something1/something2/something3/something4/something5/###### (ID is sixth segment)
• http://something1/something2/something3/something4/###### (ID is fifth segment)

I looked through forum, but couldn’t find similar problem or solution. I understand logic, but don’t know the syntax for it, so please help me:

if split_url[6] is empty (meaning that link has only 5 segments. Or - another idea - maybe somehow to check if split_url[6] is number?)
print_url = ‘http://…id=’ + split_url[5] (create link to print version of article with 5th segment)
or else
print_url = ‘http://…id=’ + split_url[6] (create link to print version of article with 6th segment)
return print_url

I hope this is possible, I just don't know how.