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Silvayn · 11-19-2007, 03:15 PM

Hmm,

ok, i'm trying to get a printed version url, but i don't know the required string handling commands for python

i need
http://www.sme.sk/c/3592953/Ceskoslovenska-esej.html

to become
http://www.sme.sk/clanok_tlac.asp?cl=3592953

I know of 'replace'...

def print_version(self, url):
return url.replace('/c/', '/clanok_tlac.asp?cl=')

but how do i get rid of the "/Ceskoslovenska-esej.html" at the end?

11-19-2007, 03:15 PM	#45
Silvayn Member Posts: 10 Karma: 10 Join Date: Jun 2007 Location: Slovakia Device: HTC Touch Diamond, Sony Reader 505	Hmm, ok, i'm trying to get a printed version url, but i don't know the required string handling commands for python i need http://www.sme.sk/c/3592953/Ceskoslovenska-esej.html to become http://www.sme.sk/clanok_tlac.asp?cl=3592953 I know of 'replace'... def print_version(self, url): return url.replace('/c/', '/clanok_tlac.asp?cl=') but how do i get rid of the "/Ceskoslovenska-esej.html" at the end? Last edited by Silvayn; 11-19-2007 at 03:25 PM.