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TonytheBookworm · 09-29-2010, 02:27 PM

maybe this will work:

Code:

return url.replace('\"', '\%22)

09-29-2010, 02:27 PM	#3
TonytheBookworm Addict Posts: 264 Karma: 62 Join Date: May 2010 Device: kindle 2, kindle 3, Kindle fire	maybe this will work: Code: return url.replace('\"', '\%22)