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Old 07-27-2010, 04:44 AM   #3
pdurrant
The Grand Mouse 高貴的老鼠
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Quote:
Originally Posted by obs20 View Post
Spoiler:
I'd say the THH requires less tosses because as you finish the task of counting for THT the last element of T is already there.

Let me clarify. There is no overlap in the sequences, even when going from one task to the next. When you finish monitoring for THT, you start monitoring for THH starting with the next coin toss, not the last one of THT. (Question edited to clarify this point.)
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