I'm not sure what you're asking for is feasible. What you've described is something that would be more suited to an external program/algorithm (or a plugin) rather than one single Regular Expression. Finding all 15 with one expression wouldn't be the hard part... replacement based on "if/then" logic is where it would fall apart.

OK. Thanks for your answer. I will try to find another solution

You could create a simple sed script with one line for each character that you need to fix. E.g.

Then simply save the lines as a utf8 text file (without BOM), e.g. fix.sed, and execute it with sed:

(Note that this will overwrite the original files.)

@Doitsu

Wow!! It's working very well! Thanks a lot!!
What means BOM?

Sorry, I was only thinking in terms of the F&R regex feature of Sigil. :o

No sorry, me too :)

BOM = byte order mark.

At least the Windows GNU sed port requires that both the .html files and the sed script be utf8 files without byte order marks. AFAIK, .html files created by Sigil are automatically saved without BOMs. I.e. you only have to make sure that the sed script doesn't have one either.

Every now and then you may want to widen your horizon. :D
But you are of course right, Sigil doesn't do sed.

That's when even rudimentary sed or Perl skills come in handy.

But I suffer from acute agoraphobia. :D

Thanks all for the lesson. :)

Hi! I'm looking for an expression that erase "- " but not " - ".
(example: sim- ple, not: word - word).
Could somebody help me??

search: ([a-z])-([a-z])

replace: \1\2

only if surrounded by lowercase letters BUT :eek: it also gets legitimate hyphenated words

There's no real way of knowing that only complete words are on either side of the hyphen, but strictly in keeping with what you asked...

Find: (?<!\s)-\s Or: \w\K-\s
Replace: <empty/blank>

Please test first, and do keep in mind that there's many situations in normal written text where what you're looking for will (and should) occur. I certainly wouldn't suggest using "Replace all" but it may help you narrow down the occurrences enough where you can sign off on each and every replacement.

Help! I am clueless about regex. I have a Word document I saved as HTML Filtered (sure didn't seem to filter much!). I imported it into Calibre and converted to ePub. Between MSO and Calibre I ended up with over 41,000 :( rows in the CSS. Every paragraph has its own class. Examples:
<p class="MsoNormal79"><span class="calibre14">
<p class="MsoNormal80"><span class="calibre20">
<p class="MsoNormal81"><span class="calibre20">
<p class="MsoNormal82"><span class="calibre17">

I want them all to say:
<p class="paragraphtext">

Can I put something in find to replace them all at once?:help:

Karen

You could very well end up with a disaster if you're not careful. I would start with the paragraphs first as spans can get a bit hairy.

If you're absolutely sure that you want to change everything that has a class name of "MsoNormalXX" (X being numerals) to "paragraphtext", then:

Find: <p class="MsoNormal\d+">
Replace: <p class="paragraphtext">

Make sure you have good backups in case things don't turn out the way you've planned.