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 01-06-2013, 12:07 PM #10501 Bilbo1967 Not scared!     Posts: 10,127 Karma: 42714289 Join Date: Mar 2009 Location: Midlands, UK Device: Sony 600, Sony 650, Sony T2, Xoom, Nexus 7 (2012 & 2013), Nook ST (x2) For the anagram of STAGNATION, ANTAGONIST?
01-06-2013, 12:48 PM   #10502
orlok
Finish that damn book!

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Quote:
 Originally Posted by Bilbo1967 For the anagram of STAGNATION, ANTAGONIST?
Correct! It's one that keeps people guessing as they often assume it's going to be something ending in ING.

01-06-2013, 12:50 PM   #10503
Bilbo1967
Not scared!

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Quote:
 Originally Posted by orlok Correct! It's one that keeps people guessing as they often assume it's going to be something ending in ING.
Yep, I wasted a lot of time trying to come up with something ending in ING

01-06-2013, 12:50 PM   #10504
pdurrant
The Grand Mouse 高貴的老鼠

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Quote:
 Originally Posted by pdurrant 101 - 102 = 1 Move one number to make the equality correct. (And I don't mean move a 1 over the = to make an ≠ sign! It should remain an equality, not an inequality.)
No-one?

01-06-2013, 12:53 PM   #10505
orlok
Finish that damn book!

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Quote:
 Originally Posted by pdurrant 101 - 102 = 1 Move one number to make the equality correct. (And I don't mean move a 1 over the = to make an ≠ sign! It should remain an equality, not an inequality.)
Does it have to conform to the "proper" rules of equations? In other words, if I moved the 1 to the left-hand side of the equation, would it now become a negative? If not, you could have:

1 + 101 - 102 = 0 (I know, I'm pushing it a bit here...)

01-06-2013, 12:53 PM   #10506
Bilbo1967
Not scared!

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Quote:
 Originally Posted by pdurrant No-one?
It's beyond me I'm afraid.

01-06-2013, 12:57 PM   #10507
pdurrant
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Quote:
 Originally Posted by orlok Does it have to conform to the "proper" rules of equations? In other words, if I moved the 1 to the left-hand side of the equation, would it now become a negative? If not, you could have: 1 + 101 - 102 = 0 (I know, I'm pushing it a bit here...)
I can see I've been imprecise. Move one digit to make the equality correct.

(But no, you're not allowed to add a plus sign.)

 01-06-2013, 12:58 PM #10508 pdurrant The Grand Mouse 高貴的老鼠     Posts: 43,095 Karma: 127572163 Join Date: Jul 2007 Location: Norfolk, England Device: Kindle Voyage OK. BIG clue. The right side of the equality doesn't change.
 01-06-2013, 03:47 PM #10509 Billi Wizard     Posts: 3,349 Karma: 14052629 Join Date: Jun 2009 Location: Berlin Device: Cybook, iRex, PB, Onyx Move the 2 up that it is the power of 10 (100).
 01-06-2013, 04:23 PM #10510 pdurrant The Grand Mouse 高貴的老鼠     Posts: 43,095 Karma: 127572163 Join Date: Jul 2007 Location: Norfolk, England Device: Kindle Voyage Yes! Congratulation, Billi. Over to you for the next question.
01-06-2013, 04:46 PM   #10511
orlok
Finish that damn book!

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Quote:
 Originally Posted by Billi Move the 2 up that it is the power of 10 (100).
Well done Billi. That was driving me mad.

01-07-2013, 02:49 AM   #10512
pdurrant
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Quote:
 Originally Posted by pdurrant There's a grassy field. 11 goats on the field will eat all the grass in seven days and then starve. 10 goats would finish all the grass in 8 days and then starve. How long could three goats survive on the field?
While I solved this a complicated mathematical way, there's also a simpler mathematical way to solve it:

In the first scenario there are 77 goat days of food. In the second case, there is 80 goat days. Therefore the field produces enough grass each day to sustain 3 goats, and so the 3 goats could live there forever.

(Once again, credit to Richard Wiseman's blog)

 01-07-2013, 06:17 AM #10513 Billi Wizard     Posts: 3,349 Karma: 14052629 Join Date: Jun 2009 Location: Berlin Device: Cybook, iRex, PB, Onyx Sorry for the delay. Another little math task: SECHS +SECHS -------- ZWOELF Replace the letters with the right numbers! Sorry, couldn't manage to get the letters straight one beneath the other, but I'm sure you know what is meant!
 01-07-2013, 07:13 AM #10514 pdurrant The Grand Mouse 高貴的老鼠     Posts: 43,095 Karma: 127572163 Join Date: Jul 2007 Location: Norfolk, England Device: Kindle Voyage Code: ```+SECHS +SECHS ====== ZWOELF``` Z F W C L S H O E Code: ```+69476 +69476 ====== 138952``` Z must be 1 (since even 99999+99999 = 199998). E must be >=5, sinze W≠F F must be even W must be F+1 F can't be zero, since Z=1 and W≠Z S must be > 5 since Z=1 and F≠0 L must be odd since S>5 None of the top letters can represent zero, as the corresponding sum would be the same letter or Z (1), which doesn't happen. With these restraints, it's fairly easy to go through the possibilities. Last edited by pdurrant; 01-07-2013 at 07:30 AM.
 01-07-2013, 07:26 AM #10515 Stitchawl Opsimath     Posts: 12,344 Karma: 187123187 Join Date: Mar 2009 Location: Chiang Mai, Northern Thailand Device: Sony PRS-650, iPhone 5, Kobo Glo, Sony PRS-350, iPad, Samsung Galaxy ... must be. Stitchawl