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Old 07-08-2011, 05:26 AM   #1
pimpoum
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search and replace with incremental number

Hi,

I'm looking for a software (a free one if possible) that can search through a html file and replace the replacement string with an incremental number.

I've looked around a bit but can't find it. Anyone has any ideas?

Thanks a lot
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Old 07-08-2011, 06:14 AM   #2
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vim can: http://imhotep.koalabs.org/?p=121
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Old 07-08-2011, 06:45 AM   #3
pimpoum
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Hey, thanks for replying,

I had already found the webpage you're talking about but I don't have a clue as to how to use this with vim.

I downloaded vim (for windows), got a GUI to open but that's it. Where should i put this?

thanks
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Old 07-08-2011, 08:49 AM   #4
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I don't know, I've never used it with a GUI, always in a text console. You better get a tutorial on vim, because it's not like notepad... While in command (not edit) mode, you write ":let i=1|etc.", without the quotes (note the colon).
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Old 07-08-2011, 02:41 PM   #5
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Do you have Perl installed? If not you can install Strawberry perl.

Copy the following code to a file called "bump_number.pl".

Then you can convert the string to a increasing number like this:

Open a Command window (Start->Run->"cmd")

type my_page.html | perl bump_number.pl > my_page_2.html

The new file "my_page_2.html" will have your string replaced with a number that increases from 1.

WARNING: This code assumes your target string only appears 1 time per row. In the example below the word "Buick" appeared twice on the same row and both strings were given the same number.

Code:
#!/usr/bin/perl
# Perl script that will:
# - Read each row from standard input
# - Look for a sub-string and replace it with a number
# - Bump the nunber
# - Write each row out to standard output.
#
# Example:
# If your input file is my_page.html you do this:
#       type my_page.html | perl bump_number.pl > my_page_2.html
#
my $lTargetString = 'Buick';
my $lNumber = 1;
my $lRow;

while ( $lRow = <STDIN> ) {
        chomp ($lRow);
        if ( index ( $lRow, $lTargetString ) > -1 ) {
                $lRow =~ s/$lTargetString/$lNumber/g;
                $lNumber++;
        }
        print "$lRow\n";
}
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