03-14-2011, 11:14 AM | #1 |
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getting the print version
How to get print version if link to page view as:
http://domain.tld/category/subcategory/[number]-[title] and print version: http://domain.tld/category/subcategory/[number]/print Actually I need to replace the "hyphen" and everything that comes after it to "/print" |
03-17-2011, 11:42 AM | #2 |
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I think:
Code:
import re def print_version(self, url): return re.sub(r'([0-9]*)\-.*', r'\g<1>/print', url) |
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03-17-2011, 12:13 PM | #3 |
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Uunfortunately did not work.
XML: http://k.img.com.ua/rss/ru/kyiv.xml Example page: http://korrespondent.net/kyiv/119700...ka-v-etom-godu Example print page: http://korrespondent.net/kyiv/1197007/print |
03-18-2011, 06:48 AM | #4 |
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Code:
def print_version(self, url): return url+'/print' |
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