Originally Posted by WS64
No, \B is "not word boundary"
I thought you meant "– bla" was fine and "–bla" was not, and with –\B you should find "–bla"
But actually I am wrong, you need \b (although I do not understand why), so "–\b" will find "–bla".
Of course if – got replaced by - this will not really work anymore
You are correct the -\b would find it.
I want another 'AND' condition: Spelling error, since -\b is valid in many, many, cases.