Greetings,

Please have some patience as I'm not a python/web/html/soup developer :)

I am trying to return the print version of an article from an rss feed. The url looks something like this:

http://www.news24.com/Content/SouthAfrica/News/1059/1cfd873e535e4b5ab944da15f15aff46/04-10-2009%2008-08/CT_faces_huge_maintenance_bill

The print version url looks like this:

http://www.news24.com/printArticle.aspx?iframe&aid=1cfd873e-535e-4b5a-b944-da15f15aff46&cid=1059

The problem is that the print url is supplied through a java script:
<script language="JavaScript">
function openPrintWindow() {
myPrintWindow = window.open('http://www.news24.com/printArticle.aspx?iframe&aid=1cfd873e-535e-4b5a-b944-da15f15aff46&cid=1059','myPrintWindow','toolbar=0,location=0,di rectories=0,status=0,menubar=0,scrollbars=1,resiza ble=0,width=750,height=600');
}
</script>

So, what is the easiest way to grab that URL from the java script? I've looked at some of the builtin recipes but could not find anything that relates to a specific case like this. Or maybe I just didn't understand the python code ;)

Any help appreciated.
Regards,
Neels

use a regular expression to match the text in the javascript.

Ok,

A little example:
Q: How do I travel from Z to Y?
A: Use an automobile.

Not to belittle the regular expression answer, but .... uhhmmmm HOW? Does anyone have some sample code using regular expressions?

Regards,
Neels

is the javascript in the feed file or in the html linked to by the rss feed?

This is what you should use:


def print_version(self, url):
artl = url.rpartition('/')[0]
artl2 = artl.rpartition('/')[0]
rrest, sep, aid= artl3.rpartition('/')
cid = rrest.rpartition('/')[2]
return 'http://www.news24.com/printArticle.aspx?iframe&aid=' + aid + '&cid=' + cid

Thanks!! Will try that tonight. Much appreciated.

<edit>

PERFECT. I will study it a bit as there is another site using a similar method and post both recipes when done.

Thanks again.